Here is a table that maps the ASIC with the "Available ports and Disabled ports" after performing portchannelization in the QFX10000-30C line card:
Table: Port Mapping for Channelization
ASIC Available Ports Disabled PortPE0 0, 2, 4, 8 6PE1 10, 12, 14,18 16PE2 20, 22, 24,28 26PE3 1, 3, 5, 9 7PE4 11, 13, 15,19 17PE5 21, 23, 25,29 27
Here, the physical ports associated with PE0 ASIC are 0, 2, 4, 6 and 8. The documentation mentions that every 5th port is disabled once port channelization is performed. This would mean that the fifth port is port 8 and port 8 must have been disabled for PE0. But the documentations shows port 6 being as disabled for PE0. Similary for the ASICs PE1, PE2, PE3, PE4 and PE5 the fifth must have been 18,29,9,19 and 29 while the documentation shows the fifth disabled port as 16,26,7,17 and 27.
Could someone please help very if I am understanding the logic incorrectly, or the documentation needs tobe updated?
Here is the juniper documentation being referenced:
Unlike the QFX10000-36C line card, the QFX10000-30C line card does not have port groups; port behavior is tied to the ASIC associated with the port.
The switch, as a whole, does not have port groups; however, within the ASIC, there are four-port groups shared by the five physical ports. When one of the ports in the port group is channelized, the fifth port is disabled and cannot be channelized. If ports in all 12 ASICs are channelized, the switch has a maximum of 192 10-Gigabit Ethernet interfaces. this is for a QFX10000-60 C but i am just pasting this to you for better understanding.
Physical Ports Available for Channelization
Physical Ports that Become Disabled
The port group must be configured using the set chassis fpc pic port channel-speed command. For example, to channelize the first switch port, use the set chassis fpc 0 pic 0 port 1 channel-speed 10g command.
In the above table, consider (8,9), (10,11), (12,13), (14,15) are available for channelization, (16,17) is not available for channelization. Except for the first set of available ports (0,1),(2,3)(4,5), the logic I mentioned in my previous sentence works for all other ports. Upon checking, the same is true for QFX10000-30C as well.
The below document should help you clarify better:
Hope this helps 🙂
Please mark "Accepted Solution" if this helps you understand.
Kudos would be much appreciated too 🙂
I have edited my previous response for more clarity. Please let me know if there are further doubts regarding this.
Thank you for the reply. But I still have doubts.
I guess what I’m trying to understand is what is taken into consideration for port 6 to be disabled in PE0.
Are ports 0,2,4,6,8 part of ASIC PE0? If so, the documentation mentions that the 5th port should be disabled. If this is the case, counting from left to the right, the 5th port should have been 8 and not 6. But port 6 is seen as being as disabled after channelization for the QFX1000-30C line card.
Please refer to the Disabled port in channelized port (figure 2) for clarity about this.
If you see the diagram, you can see that ports are numbered as (0,1) in one column, (2,3) in the second column, (4,5) the third column and so on.
Let me represent it here for you: ( underlined ports are 5th ports in each row)
0 2 4 6 8 10 12 14 16 18 20 22 24 26 28
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29
Considering each row in the above representation, except for the first set which seems like 4th port is disabled ( but if you imagine the above rows as a loop, here also the fifth port is disabled if you consider 28,0,2,4 which are available, 6 becomes 5th port and in the second row similarly 7 becomes disabled 5th port while 29,1,3,5 are available)
Example: 28,0,2,4 are available and 6 is disabled --- ROW 1
29,1,3,5 are available and 7 is disabled --- ROW 2
8,10,12,14 are available and 16 is disabled ---- ROW 1
9,11,13,15 are available and 17 is disabled --- ROW 2
18,20,22,24 are available and 26 is disabled --- ROW 1
19,21,23,25 are available and 27 is disabled --- ROW 2
If you want to continue with next port, it is 28 in ROW 1 and 29 in ROW 2, applying the same fifth port disable the rule, you will get the first combination again----- 28,0,2,4 are available and 6 is disabled ( row 1) and 29,1,3,5 are available and 7 is disabled (row 2)
I hope this clarifies your doubt now.
Please mark "Accept as Solution" for this post if this helps you.
That definitely clears my doubt. I feel incredibly lucky to be part of such a great community. Thank you for taking the extra mile for explaining the details, just reading the documentation alone, I would have never figured it out.
Glad I could help 🙂
Thanks for acknowledging the solution as Accepted. !